Programming Examples

Write a program to create calculator


Write a program to calculate (1) Addition, (2) Subtraction, (3) Multiplication, (4) Division, (5) Remainder calculation, (6) Larger out of two numbers by using switch statements?

Solution

#include<stdio.h>
void main (){
int a,b,c,ch;
clrscr();
printf(“\t =================”);
printf(“\n\t MENU”);
printf(“\n\t =================”);
printf(“\n\t[1] ADDITION”);
printf(“\n\t[2] SUBTRACTION”);
printf(“\n\t[3] MULTIPLICATION”);
printf(“\n\t[4] DIVISION”);
printf(“\n\t[5] REMAINDER”);
printf(“\n\t[6] LARGER OUT OF TWO”);
printf(“\n\t[0] EXIT”);
printf(“\n\t=================”);
printf(“\n\n\t ENTER YOUR CHOICE :”);
scanf(“%d”, &ch);
if(ch<=6 & ch>0)
{
 printf(“Enter Two Numbers :”);
 scanf(“%d %d”,&a,&b);
}
 switch ( ch)
 {
 case 1 :
 c=a+b;
 printf(“\n Addtion : %d”,c);
 break;
 case 2 :
 c=a-b;
 printf(“\n Subtraction : %d”,c);
 break;
 case 3 :
 c=a*b;
 printf(“\n Multiplication : %d”,c);
 break;
 case 4 :
 c=a/b;
 printf(“\n Division : %d”,c);
 break;
 case 5 :
 c=a%b;
 printf(“\n Remainder : %d”,c);
 break;
 case 6 :
 if(a>b)
 printf(“\n\t %d (a) is larger than %d (b).”,a,b);
 else
 if(b>a)
 printf(“\n\t %d (b) is larger than %d (a).”,b,a);
 else
 printf(“\n\t %d (a) & %d (b) are same.”,a,b);
 break;
 case 0 :
 printf(“\n Terminated by choice”);
 exit();
 break;
 default :
 printf(“\n Invalid Choice”);
 }
getch();
}
Output

OUTPUT:

MENU

=================

[1] ADDITION

[2] SUBTRACTION

[3] MULTIPLICATION

[4] DIVISION

[5] REMAINDER

[6] LARGER OUT OF TWO

[0] EXIT

=================

ENTER YOUR CHOICE : 6

Enter Two Numbers : 8 9

9 (b) is larger than 8 (a)

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