**Programming** Examples

# Calculate the total interest

Calculate the total interest based on the following.

PRINCIPLE AMOUNT (Rs.) | Rate of Interest (Rs.) |

>=10000 | 20% |

>=8000 && <=9999 | 18% |

<8000 | 16% |

`Solution`

```
void main()
{
float princ,nyrs,rate,interest;
clrscr();
printf(“\n Enter Loan & No. of years :-”);
scanf(“%f %f”, &princ, &nyrs);
if(princ>=10000)
rate=20;
else
if(princ>=8000 && princ<=9999)
rate=18;
else
if(princ<8000)
rate=16;
interest = princ * nyrs * rate/100;
printf(“\nYears : %6.2f”,nyrs);
printf(“\nLoan : %6.2f”,princ);
printf(“\nRate : %6.2f”,rate);
printf(“\nInterest : %6.2f”,interest);
getche();
}
```

`Output`

Enter Loan & No. of years :- 5000 3

Loan : 5000.00

Years : 3.00

Rate : 16.00

Interest : 2640.00

Explanation:

In the above program, the loan and the number of years are entered through the keyboard.
The entered principal amount is checked with the if statement. Based on the principal
amount, the rate of interest is charged. The interest is calculated by considering different
factors such as loan amount, the number of years and the rate of interest as per the table