What will be the output of the following Python code?
x = "abcdef" i = "a" while i in x[:-1]: print(i, end = " ")
a a a a a
a a a a a a
a a a a a a … infinite Time
a
x = "abcdef" i = "a" while i in x: x = x[1:] print(i, end = " ")
no output
error
x = 'abcd' for i in x: print(i) x.upper()
a B C D
a b c d
A B C D
x = 'abcd' for i in range(x): print(i)
0 1 2 3
none of the mentioned
x = 'abcd' for i in range(len(x)): print(i)
1 2 3 4
x = 'abcd' for i in range(len(x)): print(i.upper())
What will be the output of the following Python code snippet?
x = 'abcd' for i in range(len(x)): i.upper() print (x)
x = 'abcd' for i in range(len(x)): x[i].upper() print (x)
abcd
ABCD
x = 'abcd' for i in range(len(x)): x = 'a' print(x)
abcd abcd abcd
a a a a
x = 'abcd' for i in range(len(x)): print(x) x = 'a'
abcd abcd abcd abcd
d = {0: 'a', 1: 'b', 2: 'c'} for i in d: print(i)
0 1 2
a b c
0 a 1 b 2 c
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.keys(): print(d[x])
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.values(): print(x)
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.values(): print(d[x])
d = {0, 1, 2} for x in d.values(): print(x)
None None None
d = {0, 1, 2} for x in d: print(x)
{0, 1, 2} {0, 1, 2} {0, 1, 2}
d = {0, 1, 2} for x in d: print(d.add(x))
0 1 2 0 1 2 0 1 2 …
None of the mentioned
for i in range(0): print(i)
0
for i in range(2.0): print(i)
0.0 1.0
0 1
for i in range(int(2.0)): print(i)
